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From figure, it is clear that we have two capacitors $C_{1}$ and $C_{2}$. Positive plates of $C_{1}$ are connected to positive plate of $C_{2}$ and negative plate to negative. Therefore $C_{1}$ and $C_{2}$ are in parallel.

So, $C_{p}=C_{1}+C_{2}=2C=d2ε_{0}a $

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